Question 1
consider the number 5. select all of the categories that the number falls into.
natural
integer
rational
irrational
real
imaginary
complex
question 2
consider the number sqrt(2). select all of the categories that the number falls into.
natural
integer
rational
irrational
real
imaginary
complex
question 3
consider the number 7/13. select all of the categories that the number falls into.
natural
integer
rational
irrational
real
imaginary
complex
question 4
consider the number 5i. select all of the categories that the number falls in
natural
integer
rational
irrational
real
imaginary
complex
question 5
consider the number 0. select all of the categories that the number falls into.
natural
integer
rational
irrational
real
imaginary
complex

1) 5 = Natural, Integer, Rational, Real

2) = Irrational, Real

3) = Rational, Real

4) = Imaginary , Complex

5) 0 =  Integer, Rational, Real

Step-by-step explanation:

We have to find the  categories that the number falls into.

So first we define the terms,

Natural number - The positive integers (whole numbers) 1, 2, 3, etc., and sometimes zero as well.

Integers number - A whole number; a number that is not a fraction.

Rational number - A number that can be in the form p/q , where p and q are integers and q is not equal to zero.

Irrational number - A number that cannot be in the form p/q , where p and q are integers and q is not equal to zero.

Real number - A real number is a whole number, rational and irrational but not imaginary and infinity.

Imaginary number - When squared a number, gives a negative result represent as .

Complex number - It is a combination of a  real Number and an imaginary Number.

Now, categories the number

1) 5 = Natural, Integer, Rational, Real

2) = Irrational, Real

3) = Rational, Real

4) = Imaginary , Complex

5) 0 =  Integer, Rational, Real

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.