Abin contains 78 light bulbs of which four are defective. if five are randomly selected from the bin without replacement, find the probability that all five are not defective.

0.7630

Step-by-step explanation:

Probaility of defective = 4/78

Probability of NOT defective = 1 - 4/78 = 74/78

Note: probability of NOT A = 1 - probability of A

Since without replacement, we need to consider that with each turn, 1 goes down from total and we multiply all the 5 outcomes, hence:

Probability 5 not defective =

THis is the answer, 0.7630

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer