What values are solutions of 0 =2xexponent of 2 -6x-8

x = -1 and x = 4

Step-by-step explanation:

Firstly solve the quadratic expression of

2x^2-6x-8 = 0it gives you the two brackets of(2x-8)(x+1)=0

then...you equate the two brackets to 0.separately

2x-8 = 0which gives you...x = 4...as the first solution..then..;

x+1 = 0which gives you...x = -1...as the second solution

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step-by-step explanation:

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column