A^2+10a+24 does anyone know how to do it

(a  + 4)(a + 6)

Step-by-step explanation:

f(a) = a² + 10a + 24

I think you are asking us to factor the quadratic.

1. Multiply the leading coefficient and the constant

1 × 24 = 24

2. Find two numbers that multiply to give 24 and add to give 10.

Possible pairs are 1, 24; 2, 12; 3, 8; 4, 6

Start with the numbers near the end of the list.

By trial and error, you will find that 4 and 6 work:

4 × 6 = 24 and 4 + 6 = 10

3. Rewrite 10a as 4a + 6a

a² +4a + 6a +24

4. Factor by grouping the first two and the last two terms

a(a + 4) + 6(a + 4)

5. Distribute the a + 4

(a  + 4)(a + 6)

a² + 10a + 24 = (a  + 4)(a + 6)

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

step-by-step explanation:

the shape,the size and the distance