What is the solution to 3x^2-2+4=0
explain answer. i'm taking a practice test and don't understand this.

There are no real solutions

Step-by-step explanation:

Recall that for a quadratic equation in the form:

ax² + bx + c = 0

using the quadratic formula, that the discriminant of the formula is given by the following expression

Discriminant = b² - 4ac

If b² - 4ac < 0 > No real roots

If b² - 4ac > 0 > Two real roots

If b² - 4ac = 0 > One real roots

In our case, a = 3, b = -2 and c = 4

b² - 4ac = (-2)² - 4(3)(3) = 4 - 36 = -32 (which is <0)

Hence there are no real roots.

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .