Machine x can make 3 widgets in 1.5 hours. working together but independently, machines x and y can make 7.5 widgets in 2.5 hours. if both machines started working at the same time and each produced 3.5 widgets, and if machine x finished at noon, at what time did machine y finish? '

At 01:45 pm machine Y will finish the work.

Step-by-step explanation:

Machine X can make 3 widgets in 1.5 hours.

So per hour production of machine X = widgets

Let rate of production of machine Y = y gadgets per hour

Now it is given that machines X and Y can make 7.5 widgets in 2.5 hours.

So per hour rate of production by both the machines = widgets per hour

Then production rate of machine X + production rate of machine Y = Rate of production by both the machines X and Y

2 + y = 3

y = 3 - 2

y = 1 widget per hour

Both the machines started working at the same time and they produced 3.5 widgets.

Then time taken by machine X with the rate 2 widgets per hour =   hours

If machine X finished at noon then the time at which both the machines started working = 12 : 00 - 1 hour 45 minutes

= 10 : 15 am

Time taken by machine Y with the rate 1 widget per hour = hours

So the time by which machine Y will finish = 10:15 am + 3.5 hours

= 01:45 pm

Therefore, at 01:45 pm machine Y will finish the work.

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

hope this < 3

heyyy

step-by-step explanation: