![\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](/tpl/images/0174/2424/69f49.png)
![\bf \stackrel{vertex}{(2,-3)}~~ \begin{cases} h=2\\ k=-3 \end{cases}\implies y = a(x-2)^2-3 \\\\\\ \stackrel{passes~through}{(4,-1)}~~ \begin{cases} x=4\\ y=-1 \end{cases}\implies -1=a(4-2)^2-3\implies 2=a(4-2)^2 \\\\\\ 2=a(2)^2\implies 2=4a\implies \cfrac{2}{4}=a\implies \cfrac{1}{2}=a \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=\cfrac{1}{2}(x-2)^2-3~\hfill](/tpl/images/0174/2424/4fb58.png)
Someone me. use the given values to write a quadratic equation of the form f(x)=ax^2+bx+c:
a)...
Mathematics, 12.08.2019 03:10 keilyjaramillo2870
Someone me. use the given values to write a quadratic equation of the form f(x)=ax^2+bx+c:
a) f(1)=3. f(2)=5. f(3)=9
b) f(0)=1. f(2)=-1 and f(-2)=7
c) vertex (2, -3) passing through the point (4, -1)
Answers: 1
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Last one and the bottom answer choice is y=(x-4)^2+1 you guys!
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