Write each number in scientific notation

d= 5.6         10^7

e = 2            10

f =  4.5013   10^-1

g =  8.9        10^-2

h =  2.6        10^-4

i =  6.98        10^-7

j =  1.2          10^-2

Step-by-step explanation:

you put a decimal in front of the first number

d:  would be  10^7 which gives you 5.6

e:  is a fraction which you convert into a decimal which gives you 2

f: you move you decimal in front of 4 to get 4.5013

g:  move your decimal in front of 8

h:  you get rid of you zeros and put the decimal in front of 2

i: move the zeros and put decimal in front of 6

j:  you move you decimal 2 places then put the decimal in front of 1:

heudhduxhdnshenebdutbbt

step-by-step explanation:

hrhhdhdbbrurb ees

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.