Which shows the equation below written in the form ax2 + bx + c = 0?
x + 10 = 3(x - 1)^2
a. 3x2 - 5x + 13 = 0
b. 3x2 -7x+ 13 = 0
c. 3x2-77-7 = 0
d. 3x2 - 5x- 7 = 0

3x² - 7x - 7 = 0

Step-by-step explanation:

Given

x + 10 = 3(x - 1)² ← expand the factor

x + 10 = 3(x² - 2x + 1) ← distribute by 3

x + 10 = 3x² - 6x + 3 ( subtract x + 10 from both sides )

0 = 3x² - 7x - 7 or

3x² - 7x - 7 = 0

answer: can you me with homework?

step-by-step explanation:

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐