Aclinical trial tests a method designed to increase the probability of conceiving a girl. in the study 345 babies were born, and 276 of them were girls. use the sample data to construct a 99% confidence interval estimate of the percentage of girls born. based on the result, does the method appear to be effective?

Answer with explanation:

Given : A clinical trial tests a method designed to increase the probability of conceiving a girl.

Also, in a normal case the probability of conceiving a girl is 0.5.

Let p be the proportion of girls born.

Then , we have

Sample size : n= 345

The sample proportion of girls born =

Critical value :

The confidence interval for population proportion is given by :_

Since the confidence interval do not contains 50% that means there is increase in the probability of conceiving a girl, then it can be concluded that we have statistical evidence that the the clinical trial method increase the probability of conceiving a girl.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

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step-by-step explanation: