Set x consists of eight consecutive integers. set y consists of all the integers that result from adding 4 to each of the integers in set x and all the integers that result from subtracting 4 from each of the integers in set x. how many more integers are there in set y than in set x?

Step-by-step explanation:

Given that X consists of 8 consecutive integers

say X ={n,n+1,...n+8}

Set Y is formed by adding 4 to each and also subtracting 4 from each element of X

Numbers got by addition = n+4, n+5,...n+12

Numbers got by subtraction = n-4,n-3,n-2,n,n+1, n+2, n+3,n+4

We find that n+4 is repeated in both.

Hence Y ={n-4,n-3,...n+4,...n+12}

n(Y) = 15

Y has 7 integers more than X

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.