4boys step off from the same place. if their steps measures 16cm,28cm,40cm and 77cm respectively. at what distance from the starting point will they step together again?

  6160 cm

Step-by-step explanation:

The distance will be the least common multiple of these numbers. That can be figured by looking at their prime factors and choosing the smallest product that contains them all.

  16 = 2⁴

  28 = 2²·7

  40 = 2³·5

  77 = 7·11

The factors we need to include are 2⁴, 5, 7, 11. The product of these is

  2⁴ × 5 × 7 × 11 = 6160

The boys will step together again after 6160 cm.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !