Markin ! plz !
over the interval (13), the average rate of change of g is greater than the average rate of change of f.
as the value of x increases, the average rates of change of f and g (remain constant and constant and and and and increase) , respectively.
when the value of x is equal to 8, the value of (f(x) equals the value of g((x) exceeds value of f((x) exceeds value of g(x)
it can be further generalized that a quantity increasing exponentially will () exceed a quantity increasing linearly.

Step-by-step explanation:

a) The slope of the curve g(x) roughly matches that of f(x) at about x=4. Above that point, the curve g(x) is steeper than f(x), so its average rate of change will exceed that of f(x). An appropriate choice of interval is (4, 5).

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b) As x increases, the slope of f(x) remains constant (equal to 4). The slope of g(x) keeps increasing as x increases. An appropriate choice of rate of change descriptors is (remain constant and increase).

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c) The curves are not shown in the problem statement for x = 8. The graph below shows that g(x) has already exceeded f(x) by x=7. It remains higher than f(x) for all values of x more than that. We can also evaluate the functions to see which is greater:

  f(8) = 4·8 +3 = 35

  g(8) = (5/3)^8 ≈ 59.54 . . . . this is greater than 35

  g(8) > f(8)

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d) Realizing that an exponential function with a base greater than 1 will have increasing slope throughout its domain, it seems reasonable to speculate that it will always eventually exceed any linear function (or any polynomial function, for that matter).

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

p = 6s

step-by-step explanation: