Suppose an and bn are series with positive terms and bn is known to be convergent. (a) if an > bn for all n, what can you say about an ? why? an diverges by the comparison test. an converges if and only if an ≤ 2bn. an converges if and only if an ≤ 4bn. an converges by the comparison test. we cannot say anything about an . (b) if an < bn for all n, what can you say about an ? why? an converges if and only if bn 4 ≤ an ≤ bn.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

the two may have that, even a breakdown is probably offered

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step-by-step explanation: