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solve for x. 9(x + 1) = 25 + x x = 2 x = 3 x = 4 x = 54

Solve the following: x – 2= 7

Given, x -2 = 7

=> x – 2 + 2= 7 + 2 [Adding 2 both sides]

=> x = 9

Question 2:

Solve of the following: y + 3 = 10

Solution:

Given, y + 3 = 10

=> y + 3 – 3 = 10 – 3 [subtracting 3 on both side]

=> y = 7

Question 3:

Solve the following: 6 = z + 2

Given, 6 = 2 + z

=> 6 – 2 = z + 2 – 2 [Subtracting 2 both sides]

=> 4 = z

=> z = 4

Question 4:

Solve the following: 3/7 + x = 17/7

Given, 3/7 + x = 17/7

=> 3/7 + x – 3/7 = 17/7 – 3/7 [Subtracting 3/7 on both sides]

=> x = (17 - 3)/7

=> x = 14/7

=> x = 2

Question 5:

Solve the following: 6x = 12

Given, 6x = 12

=> 6x/6 = 12/6 [Dividing 6 on both side]

=> x = 2

Question 6:

Solve the following: t/5 = 10

Given, t/5 = 10

=> t/5 * 5 = 10 * 5 [Multiply by 5 on both side]

=> t = 50

Question 7:

Solve the following: 2x/3 = 18

Given, 2x/3 = 18

=> 2x = 3 * 18

=> 2x = 54

=> x = 54/2

=> x = 27

Question 8:

Solve the following: 1.6 = y/1.5

Given, 1.6 = y/1.5

=> y = 1.6 * 1.5

=> y = 2.40

Question 9:

Solve the following: 7x – 9 = 16

Given, 7x – 9 = 16

=> 7x = 16 + 9

=> 7x = 25

=> x = 25/7

Question 10:

Solve the following: 14y – 8 = 13

Given, 14y – 8 = 13

=> 14y = 13 + 8

=> 14y = 21

=> y = 21/14

=> y = 3/2 [21 and 14 are divided by 7]

Question 11:

Solve the following: 17 + 6p = 9

Given, 17 + 6p = 9

=> 6p = 9 – 17

=> 6p = -8

=> p = -8/6

=> p = -4/3 [8 and 6 are divided 2]

Answer = A Linear Equation is an algebraic equation composed of a constant (e.g. x = 3) or a variable to the power of 1 (e.g. 2a + 3 = 13).

Remember that 2a means 2 × a.

Solving an equation is to figure out what number is represented by the variable. For example, in the equation 2a + 3 = 13, the variable a is 5. That’s what I can

The expression of this would be 3.75x+y= 23