Answer asap!
1. consider the quadratic equation. 3x^2-6=2x
(a) what is the value of the discriminant?
(b) what does the discriminant of the quadratic equation tell about the solutions to 3x^2-6=2x?
2. the length of a rectangular floor is 4 feet longer than its width w. the area of the floor is 525 ft2.
(a) write a quadratic equation in terms of w that represents the situation.
(b) what are the dimensions of the floor?
show your work.

1.

(a) The discriminant is b^2 - 4 * a * c = (-2)^2 - 4 * 3 * -6 = 76

(b) Since the discriminant is positive, the equation has two unique real solutions

2.

(a) w(w + 4) = 525, so w^2 + 4w - 525 = 0

(b) Using the quadratic equation, w = (-4 + sqrt(4^2 - 4 * 1 * -525)) / 2

(the negative solution does not make sense in the context of this problem)

So w = 21, and the length of the other side of the floor is w + 4 = 21 + 4 = 25.

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6

2 2/3 hours duhh silly

step-by-step explanation: