You select a family with three children. it m represents a male child, and f represents a female child, the set of equally likely outcomes for the children's genders is (mmm, mimf mfm, mff, fmm, fmf, ffm, fff ) find the probability of selecting a family with fewer than 5 male children p(fewer than 5 male children) type an integer or a simplified fraction.)

Answer with explanation:

→If a Family has five children, then Total likely outcome can be represented as:

Five Male =1

Five Female =1

4 Male +1 Female =4

4 Female +1 Male =4

3 Male +2 Female =10

3 Female +2 Male =10

Total Possible Outcome

 =1+1+4+4+10+10

or

   =2×2×2×2×2

     =32

,i.e either a children can be a male or female.

→If all the five childrens are male , then in the family number of children fewer than 5 male children =32-1=31

→Probability of an Event

→→Probability of selecting a family with fewer than 5 male children

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step-by-step explanation:

$3,200 x 7.25% = $3,200 x .0725 = $232 interest monthly

$232 monthly x 12 annual = $2, 784

step-by-step explanation: