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Mathematics, 08.08.2019 02:10 FinnaCryDotJpeg

[44-4] exercise designed to employ cp twice to get an
equivalence
*. 1st proof for a -> b by cp
*. 2nd proof for b -> a by cp
*. combine them by conj
*. then use equiv
c: a < -> b
1: a -> ~c
2: ~b -> c
3: a v ~b

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Answers: 2

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[44-4] exercise designed to employ cp twice to get an
equivalence
*. 1st proof for a -&g...

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