Find the distance from the line passing through points p(0,0,0) and q(9,0,0) to the line passing through points r(3,-2,4) and s(3,-6,-8).

Step-by-step explanation:

Let the I line be PQ and II line be RS

Direction ratios  of PQ = (9,0,0) and direction ratios of RS = (0, -4, -12)

Distance between skew lines

=(a1-a2).(b1xb2)/|b1xb2|

where a1 and a2 are points

Here a1-a2 = (-3,2,-4) taking P and Q as points.

b1 = (9,0,0) and b2 = (0,-4,-12)

Shortest Distance = (a2-a1).(b1xb2)/|b1xb2|

De

Numerator = -9(-24-16)=360

Denominator vector = i(0)-j(-108)+k(-36)

Modulus  of vector =\sqrt{108^2+36^2} =36\sqrt{10}

Hence Shortest distance = \sqrt{10}

my answer is$ 12

step-by-step explanation:

because 15 -2=12

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.