Mathematics, 08.08.2019 00:20 lindasuebairdoyjpf7
Let ii be the tangent plane to the graph of f(x, y) = 8 – 2x^2 – 3y^2 at the point (1, 2,-6). let s, x² + y^2 + z = 4 be another surface. find the point on s which has tangent plane parallel to i.
Answers: 3
. The tangent plane to 
at (1, 2, -6) has equation
, and 
. The tangent plane to 
at a point 
is
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Let ii be the tangent plane to the graph of f(x, y) = 8 – 2x^2 – 3y^2 at the point (1, 2,-6). let s,...
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