Let f(x) = 8x + 6 and g(x) 1/3x + 7. evaluate g^-1 [f^-1 (2)]

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Step-by-step explanation:

given that and .

(If these weren't your functions and you understand neither way, please let me know. Thank you kindly. Have a nice day.)

Step-by-step explanation:

.

So here we want to start with the inside first.

That is, start with .

Let then

We need to solve for .

f(c)=2

8c+6=2

Subtract 6 on both sides:

8c=2-6

8c=-4

Divide both sides by 8:

c=-4/8

c=-1/2

Since then .

So now we need to find .

Let then .

So we need to solve for .

Subtract 7 on both sides:

Multiply both sides by 3:

So we have .

Another way!

We could actually find the functions that are inverses of the given functions.

The basic idea is that we need to swap x and y:

Now we need to remake y the subject.

Subtract 6 on both sides:

Divide both sides by 8:

is the inverse of .

Again the basic idea to find inverse is to swap x and y:

Now solve for y.

Subtract 7 on both sides:

Multiply both sides by 3:

is the inverse of .

Now let's find:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.