Blue whales eat an average of 5,000 pounds of fish daily, with a standard deviation of 850 pounds. approximately what percentage of blue whales eat more than 5,850 pounds of fish?

15.87% of blue whales eat more than 5,850 pounds of fish

Step-by-step explanation:

Mean = 5000

Standard Deviation = 850

We need to find P(x>5850) = ?

We can find using z-score

z = x - mean/ standard deviation

z = 5850 - 5000/850

z = 850/850

z = 1

Now, P(x>5850) = P(z>1)

Finding value of P(z>1) by looking at the z-score table

P(z>1) = 0.8413

The normal distribution gives area to the left , so subtracting it from 1 to gain the answer

1-0.8413 = 0.1587

Now, to find percentage multiply it with 100

0.1587 * 100 = 15.87 %

15.87% of blue whales eat more than 5,850 pounds of fish

 15.87%

Step-by-step explanation:

Given : Blue whales eat an average of 5,000 pounds of fish daily, with a standard deviation of 850 pounds.

i.e.

We assume that this a normal distribution.

Let x be the random variable that shows the amount of fish eaten by whales.

z-score :

For x= 5,850 pounds

By using standard normal distribution table , we have

The probability that the  blue whales eat more than 5,850 pounds of fish :-

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

answer: 8

step-by-step explanation: if you add the possibilities 5 different flavor and 3 different sizes 5+3=8