Agarden area is 30 ft long and 20 ft wide. a path of uniform width is set inside the edge. if the remaining garden is 400ft^2, what is the width of the path?

2.19 ft ( approx )

Step-by-step explanation:

Let x be the width ( in ft ) of the path,

Given,

The dimension of the garden area,

Length = 30 ft, width = 20 ft,

So, the dimension of the remaining garden ( garden excluded path ),

Length = (30 - 2x) ft, width = (20-2x) ft

Thus, the area of the remaining garden,

A=(30 - 2x)(20 - 2x)

According to the question,

A = 400 ft²,

By the quadratic formula,

⇒ x ≈ 22.8  or x ≈ 2.19,

∵ Width of the path can not exceed 30 ft or 20 ft

Hence, the width of the path is approximately 2.19 ft.

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )