Acepheid variable star is a star whose brightness alternately increases and decreases. for a certain star, the interval between times of maximum brightness is 5.7 days. the average brightness of this star is 2.0 and its brightness changes by ±0.45. in view of these data, the brightness of the star at time t, where t is measured in days, has been modeled by the function b(t)=5.0+0.45 sin (2πt/4.6), where t is measured in days. find, correct to two decimal places, the rate of increase after five days.

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

plz mark brainliest i took the test