The function s(v) = describes the side length, in units, of a cube with a volume of v cubic units. jason wants to build a cube with a minimum of 64 cubic centimeters. what is a reasonable range for s, the side length, in centimeters, of jason’s cube?

s≤4 cm.

Step-by-step explanation:

Let s be side of cube.

As we know that the volume of cube=side×side×side

Here, it is given that the volume of cube = 64 cubic centimeters.

or we can write

side×side×side=64 cubic centimeters

Taking cube root both sides

side= 4 cm

In order to build a cube with a minimum of 64 cubic centimeters,

we can take the value of s≤4 cm.

Hence, the reasonable range for s, the side length is s≤4 cm.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.