Which statement accurately describes how to reflect point a(3,-1) over the y-axis?

The answer in the procedure

Step-by-step explanation:

we know that

The rule of the reflection of a point over the y-axis is equal to

A(x,y) >A'(-x,y)

That means > The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same

so

A(3,-1) > A'(-3,-1)

The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)

therefore

To reflect a point over the y-axis

Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

15 batches are the most you can make

step-by-step explanation: