The sum of the dibits of a two digit number is 15. the number obtained by interchanging its digits exceeds the given number by 9. find the original number.

  78

Step-by-step explanation:

Interchanging the digits of a 2-digit number changes the value by a multiple of 9. The multiple is the difference between the digits of the number.

So, we have two digits that add to 15, and have a difference of 9/9 = 1. Since you're familiar with your addition facts, you know that the two digits are 7 and 8. Since the number we're looking for is the smallest of the numbers you can make with those digits, ...

  the original number is 78.

More formally, let t and o represent the tens and ones digits of the original number.

  t + o = 15 . . . . . . the sum of digits is 15

  (10o +t) - (10t +o) = 9 . . . . swapping digits increases the value by 9

The latter equation simplifies to ...

  9o -9t = 9 . . . . collect terms

  o - t = 1 . . . . . . divide by 9 . . . (note the difference of digits is 9/9=1)

Adding this to the first equation gives ...

  (t +o) +(o -t) = (15) +(1)

  2o = 16

  o = 8

  t = o -1 = 7

The tens digit is 7 and the ones digit is 8: 78.

true? is that what you're asking or do you mean something else?

312312

step-by-step explanation: