Eyjafjallajökull is a volcano in ice land. during a recent eruption, the volcano, spewed out copious amounts of ash. one small was ejected from the volcano with an initial velocity of 336ft/sec. the height h, in feet, of our ash projectile is given by the equation h= -16t2 +336t. where t is the time is seconds, assuming the volcano has no height. h=0 t=0
1. when does the ash projectile reach its maximum height?
2. what is its maximum height?
3. when does the ash projectile return to the ground?

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

what's that