Suppose a revenue function is given by: r ( q ) = − q 3 + 140 q where q is thousands of units and r ( q ) is thousands of dollars. for what value of q is revenue maximized. round your answer to the nearest tenth (one decimal place). q = incorrect thousand units

At q=6.8 the revenue is maximum. So, q=6.8 thousand units.

Step-by-step explanation:

The revenue function is

where q is thousands of units and R ( q ) is thousands of dollars.

We need to find for what value of q is revenue maximized.

Differentiate the function with respect to q.

Equate R'(q)=0, to find the critical values.

Divide both sides by 3.

Taking square root both the sides.

Find double derivative of the function.

For q=-6.8, R''(q)>0 and q=6.8, R''(q)<0. So at q=6.8 revenue is maximum.

At q=6.8 the revenue is maximum. So, q=6.8 thousand units.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.