assume the trait for brown eyes is completely dominant to blue eyes and this trait is controlled by a single gene. if 400 people in a population of 10,000 have blue eyes, how many people would be expected to be heterozygous for this trait? (hint: use the hardy-weinberg formula.)

3200 people

Step-by-step explanation:

p = The frequency of the dominant gene

q = The frequency of the recessive gene

p+q = 1

⇒p = 1-q

⇒p = 1-0.2

⇒p = 0.8

Hardy-Weinberg formula

p² + 2pq + q² = 1

Now for heterozygous trait

2pq = 2×0.8×0.2 = 0.32

Multiplying with the population

0.32×10000 = 3200

∴ 3200 people would be expected to be heterozygous for this trait.

2/5

step-by-step explanation:

87%

step-by-step explanation:

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