Acertain wire stretches 0.90 cm when outward forces with magnitude f are applied to each end. the same forces are applied to a wire of the same material but with three times the diameter and three times the length. the second wire stretches
a. 3 cm
b. 1 cm
c. 2.7 cm
d. 9 cm

Option A

Step-by-step explanation:

Given -

Length to which a wire stretches when outward forces with magnitude F are applied to each end cm

Let the length of first wire

Let the diameter of first wire

The dimension of the second wire is equal to

We know that

strain

and strain

Putting the above two equations together, we get -

For wire 1,

---------Eq(1)

For wire 2,

---------Eq(1)

Dividing equation 1 by equation 2, we get

cm

Hence, option A is correct

When the same forces are applied to a wire of the same material but with three times the diameter and three times the length of the first wire then the second wire stretches 3 cm.

Given :

Let the length of the first wire be 'L' and the diameter be 'D'. Then the length and diameter of the second wire will be:

L' = 3L

D' = 3D

The formula of strain is given by:

So, for the first wire :

  ---- (1)

For the second wire:

  ----- (2)

Now, divide equation (1) by equation (2).

Simplify the above equation.

Therefore, the correct option is A) 3 cm.

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it has to be a.

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: