Acircle is centered at (-6,3) and has a radius of 11. where does the point (3,-3) lie?

Inside the circle

Step-by-step explanation:

Use the distance formula to find the distance between the center and the point.

d = √((x₁ − x₂)² + (y₁ − y₂)²)

d = √((-6 − 3)² + (3 − (-3))²)

d = √((-9)² + (6)²)

d = √(81 + 36)

d = √117

d ≈ 10.817

This is less than the radius of 11, so the point is inside the circle.

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24

first, let's see what the pattern is.

58 - x = 47

46 - x = 36

x = 9

so this means that the term after 25 is 25 - 9:

the next term in the sequence is 16.