Aplayground merry-go-round of radius r = 1.80 m has a moment of inertia i = 255 kg · m2 and is rotating at 9.0 rev/min about a frictionless vertical axle. facing the axle, a 24.0-kg child hops onto the merry-go-round and manages to sit down on the edge. what is the new angular speed of the merry-go-round?

7 rpm = 0.73 rad/s

Step-by-step explanation:

R = Radius of merry-go-round = 1.8 m

= Moment of inertia of merry-go-round = 255 kg m²

= Moment of inertia of child

ω = 9 rev/min

m = Mass of child = 24 kg

From the conservation of angular momentum

∴ New angular speed of the merry-go-round is 7 rpm =

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

110

step-by-step explanation:

based on the question i am guessing that it is a typo for abc