If there are x teams in a sports league, and all the teams play each other twice, a total of n(x) games are played, where n(x)equalsxsquaredminusx. a softball league has 5 teams, each of which play the others twice. if the league pays $35 per game, how much will it cost to play the entire schedule?

It will cost $700 to play the entire schedule.

Step-by-step explanation:

Given :

To Find :  A softball league has 5 teams, each of which play the others twice. If the league pays $35 per game, how much will it cost to play the entire schedule?

Solution:

Equation for total no. of games when all the teams play each other twice is

Now we are given that A softball league has 5 teams, each of which play the others twice.

So, Substitute x = 5 in the given equation

So, The total no. of games = 20

Cost for 1 game = $35

So, cost for 20 games =

Hence  it will cost $700 to play the entire schedule.

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1