Write the standard form of the line that has a slope of -3/4 and y -intercept of -2. include your work in your final answer.

3x + 4y = - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - and c = - 2, hence

y = - x - 2 ← equation in slope- intercept form

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Multiply the terms in the slope- intercept form equation by 4

4y = - 3x - 8 ( add 3x to both sides )

3x + 4y = - 8 ← in standard form

add an image

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.