Mathematics, 30.07.2019 20:30 QueenNerdy889
Recall the following: theorem: (lagrange's theorem) let g be a finite group and hcg. if h is a subgroup of g, then h| divides gl. the purpose of this exercise is to show that the converse of lagrange's theorem is not true in general. recall that al is not abelian, since (1 2), (23) e a4, but (1 2)(23) + (23)(1 2). (a) count the number of elements of order 3 in al. (b) for sake of contradiction, suppose there exists a subgroup hcaof order 6. i. explain why h must be normal in a4. ii. leto e ad have order 3. suppose that o h. arrive at a contradiction. iii. conclude that we must have o eh. arrive at another contradiction. (c) conclude that, although 6 divides the order of a4, as contains no subgroup of order 6.
Answers: 2
Mathematics, 21.06.2019 13:00, bairdmatthew43
Which expression is equivalent to the expression below? (6c^2 + 3c) / (-4c + 2) / (2c + 1) / (4c - 1)a. 3c(2c-1) / (2c + 1)b. -3c(2c-1)^2 / (2c + 1)^2c. 3cd. -3c(just took the test its d. -3c)
Answers: 1
Mathematics, 21.06.2019 17:40, jackieespi1461
Multiply. write your answer in simplest form. 3/8 x 5/7
Answers: 1
Mathematics, 21.06.2019 18:10, heavenwagner
which of the following sets of data would produce the largest value for an independent-measures t statistic? the two sample means are 10 and 20 with variances of 20 and 25 the two sample means are 10 and 20 with variances of 120 and 125 the two sample means are 10 and 12 with sample variances of 20 and 25 the two sample means are 10 and 12 with variances of 120 and 125
Answers: 2
Recall the following: theorem: (lagrange's theorem) let g be a finite group and hcg. if h is a sub...
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