Given that a(t) = 1/(t + 1)^2 represents the acceleration of a particle, find its velocity and position function which have conditions v(0) = 0 and x(0) = 1. show your steps of integration well enough to demonstrate your understanding.

Step-by-step explanation:

Integrate the function of the acceleration to find the function of the velocity

Use the initial condition to find the value of the constant :

Integrate the function of the velocity to find the function of the position:

Use the initial condition to find the value of the constant :

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.