Let a and b be square matrices. show that if ab = i then a and b are both invertible, with b=a-1 and a=b-1. it is given that ab = 1. the invertible matrix theorem states that if there is an nxn matrix b such that ab = 1, then it is true that hat if there is an nxn matrix a such that ab = 1, then it is true that matrix a is not invertible. matrix a is invertible. by a-1 matrix a is invertible only if matrix b is not square. matrix a and b are both not invertible. o =a left-multiply by a-1 simplify it is given that ab = 1. right-multiply each side of the equation by bºt, abb-1 = 18-1 o=b-1 right-multiply by b-1 simplify. in conclusion, it can be stated that a and b with b = and a=
it is given that ab = 1. the invertible matrix theorem states that if there is an nxn matrix a such that ab = 1, then it is true that by a-1 matrix b is invertible. matrix b is not invertible. left-multiply by a-1 simplify. matrix b is invertible only if matrix a is not square. matrix b and a are both not invertible. n by b-1 abb-1 = 1b-1 = b-1 right-multiply by b-1 simplify. in conclusion, it can be stated that a and b with b = vand a=
in conclusion, it can be stated that a and b with b = vand a= are both not invertible, are only invertible for a+b, are both invertible are not invertible for a b enter your answer in each of the answerk
in conclusion, it can be stated that a and b with b = v and a= = enter your answer in each of the answer boxes.
in conclusion, it can be stated that a and b with b = and a= enter your answer in each of the answer boxes.