Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (13, 84) lies on its terminal side.

If P = (x,y) then formulas for each trigonometric functions are:

sin x = y/r

cos x = x/r

tan x = y/x

cot x = x/y

sec x = r/x

cosec x = r/y

where r = √(x²+y²).

First find r:

r = √(13²+84²)=√(169+7056)=√7225=85.

Then just substitute:

sin x = 84/85

cos x = 13/85

tan x = 84/13

cot x = 13/84

sec x = 85/13

cosec x = 85/84

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

600,000,000,000, or 6e14

step-by-step explanation: