With this problem fast!
let’s say we have access to planting 2 different crops, watermelons and grapes. we can find the revenue of a crop by the equation: r = (p0 + px)(n0 - nx) where r is the revenue, p0 is the starting price, n0 is the amount sold at the starting price, p is the price increase, n is the decrease in the amount sold per price increase, and x is the number of price increases. crop a: watermelons have a starting price of $12.00 per m2 of area sold. at this price, you are able to sell 45 m2 worth. for every $2.00 increase, you will sell 1 m^2 less. so the first task is to figure out how to put these values into the equation above, and turn it into a quadratic function. then you will need to find the value of x in order to make the revenue as large as possible. once you know x, the number of price increases, you can then find what you should price your watermelons per m^2 .
equation: r =
number of price increases: x=
price of watermelon per m^2=