Aprofectile is shot upward, and it's distance above the ground, in feet after s t seconds is represented by the function below. s(t)-4t^2+24t. use the number line to represent the interval on which the projectile is desce ding

Step-by-step explanation:

the curve is representing the projectile. at t=0, the projectile is on the ground.  at t=6, the projectile has finished its journey and is back on the ground.  In between t=0 and t=6 will be the projectile's peak altitude.  the point between t=0 and t=6 is t=3.  So plug in t=3 and solve for s(t), and you get 36ft.  gg

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm