Suppose that 12% of people own dogs. if two people are randomly chosen, what is the probability that they both own a dog? write your answer as a percent and round to the nearest hundredth of a percent.

Answer is   0.0144 or 1.44%

Step-by-step explanation:

It is given that 12% of the people owns dog. If we choose  one random person to owns dog then probability will become that 0.12 person owns dogs.

        Now when we choose two random person who owns dogs, then it is observed that

Let X ( both people owns dogs ) = X times X

because first person owns dog and second person also owns dog.

So the probability of both people owning dogs is 0.12 x 0.12 = 0.0144

                                                                                                     = 1.44%

answer: b.48 for

step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2