The u. s. air force requires that pilots have heights between 64푖푛.and 77푖푛.heights of women are normally distributed with a mean of 63.7푖푛.and a standard deviation of 2.9푖푛.what percent of women meet that height requirement?

46.02%

Step-by-step explanation:

Given that the U.S. Air Force requires that pilots have heights between 64.and 77.

Let X be the random variable representing the heights of women

X is normal with mean = 63.7 and std dev =2.9

Prob height lies between 64 and 77 is

Hence 46.02%  percent of women meet that height requirement

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1