Which of the following statements best describes the graph of 3x – 2y = 4?
a) it is a straight line joining the points (6, 2), (5, 1), and (7,3).
b) lt is a straight line joining the points (0, -2), (2, 1), and (-2, -5).
c) it is a curve joining the points (3,-2), (2, 3), and (4. 1).
d) lt is a curve joining the points (0, 2), (-2, -1), and (4, 1).

B

Step-by-step explanation:

This is actually in the form of ax+by=c which is called standard form for a line.

I also know it is linear because the degree is 1.  I know the degree is 1 because both variables are to the first power (you don't see this number because or ).

So the choices are between A and B.

Let's see if it satisfies A:

Checking (6,2) for (x,y):

3 x - 2 y=4

3(6)-2(2)=4

18  -   4  =4

     14    =4 is false so (6,2) is not on the given line.

Moving on to B:

Checking (0,-2) for (x,y):

3 x - 2 y=4

3(0)-2(-2)=4

0   +  4   =4

         4    =4 is true so (0,-2) is on the given line.

Checking (2,1) for (x,y):

3 x - 2 y=4

3(2)-2(1)=4

6  -  2  =4

      4    =4 is true so (2,1) is on the given line.

Checking (-2,-5) for (x,y):

3 x - 2 y=4

3(-2)-2(-5)=4

-6   +  10  =4

           4  =4 is true so (-2,-5) is on the given line.

We have that all three pairs from choice B are contained on the line given.