An isosceles triangle has a base 10 units long. if the congruent side lengths have measures to the first decimal place, what is the shortest possible length of the sides?
a) 20.1
b) 5.1
c) 4.9
d) 10.1

B

Step-by-step explanation:

The two remaining sides must add up to an amount greater than the one side you have been given.

You have been given 10.

A would work. Two values of 20.1 would exceed 10. The problem is that you need the shortest value. So, though not wrong, A is not the answer.

C: if the two other sides were just 4.9 units long, they would add to something that is 0.2 units less than 10. So C cannot be the answer.

D: Like A, D will work but that would not be the shortest distance. D is not the answer.

B: adds to 5.1 + 5.1 = 10.2.

10.2 is just greater than 10. The triangle would work and of the other three answers given, B is the best.

step-by-step explanation:

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answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: