this is solving quadratic equations
just the bottom question not the top

  " x = ;  0 " .

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Or;  write in "decimal form" ;  as:  

" x = 0.4 ;  0 " .

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Step-by-step explanation:

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Given:  

10x²  -  4x  =  0  ;  Solve for "x" .

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Factor out a "2x" from the "left-hand side" of the equation:

2x (5x - 2) = 0 ;

Note that "any value";  multiplied by "0" ;  equals "0" ;

We have 2 (two) expressions:

   1)  "  2x " ;  And:

   2)  " (5x - 2) "  ;

→ which, when multiplied together, equal "0" ;

So, set "each" of the 2 (two) expressions "equal to 0 " ;

           and solve for "x" ;

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  1)   " 2x  =  0 " ;  solve for "x" ;

Divide each side of the equation by:  "2" ;  

   to isolate "x" on one side of the equation;

   & to solve for "x" ;

             →   2x/2 = 0/2  ;

             →     x = 0 ;

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  2)   " 5x - 2 = 0 " ;   solve for "x" ;

Add "2" to each side of the equation :    

         5x - 2 + 2 = 0 + 2 ;      

to get:   5x = 2 ;

Now ; divide each side of the equation by:  "5" ;

   to isolate "x" on one side of the equation;

   & to solve for "x" ;

            5x/5 = 2/5 ;

to get:

          x = 2/5 ;

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The answer is:  " x =  ;  0 . "

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 Or;  write in "decimal form" ;  as:  

          " x = 0.4 ; 0 " .

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Hope this is helpful to you!  

    Best wishes!

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50- 250 is correct i did that one too

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.