Ineed with this long term behavior math problem.

b.

Step-by-step explanation:

The slant asymptote will only exist if the degree of the top is one more than the degree of the bottom.

Here it is the other way around.

The degree of the top is 2.

The degree of the bottom is 3.

So there is no slant asymptote.

There will be a horizontal asymptote when the degree of the bottom is more than or equal to the degree of the top.

When the degrees are equal, the horizontal asymptote will be

y=(leading coefficient of top)/(leading coefficient of bottom).

Since the degree is more on bottom than the degree on top, then the horizontal asymptote is y=0.

The answer is b, then.

For large |x| this tends to 3/x, which goes to zero, so a horizontal asymptote at y=0.

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p