Need math :
express in simplest radical form
(32x^2)^6/5

Step-by-step explanation:

We assume you intend ...

  (32x^2)^(6/5) = (2^5x^2)^(6/5) = 2^6x^(12/5) = 64x^2x^(2/5)

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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answer by yourhope:

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