find the approximate values of the trigonometric functions of θ given the following information. enter the values correct to 2 decimal places. θ is in standard position the terminal side of θ is in quadrant iii the terminal side is parallel to the line 2y - 5x + 16 = 0
sin θ =
cos θ =
tan θ =
cot θ =
sec θ =
csc θ =

Step-by-step explanation:

slope of any line is same as the tan θ . so we first try to find the slope of the given line and then using that we can find remaining trigonometric functions .

To find the slope of a line we need to change the equation of line to slope intercept form .

2y - 5x +16 =0

move all terms to right

2y = 5x - 16

divide all by 2

y = 5/2 x - 8

compare this with y =mx+b

slope = m = 5/2

It means

tan θ =  5/2 = 2.5

tan θ =  2.50

now use the trigonometric ratios (see the image attached )

sin θ =

cos θ =  

tan θ =  2.50

cot θ =  

sec θ =  

csc θ =  

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..