The second termn in a geometric sequence is 20. the fourth termn in the same sequense is 45/4, or 11.225. what is the common ratio in this sequence?

r=±0.75

Step-by-step explanation:

Given:

a2= 20

a4= 45/4

As a geometric sequence has a common ratio and is given by:

an=a1(r)^n-1

where

an=nth term

a1=first term

n=number of term

r=common ratio

Now

a2=20=a1(r)^(2-1)

20=a1(r)^1

20=a1*r

Also

a4=45/4=a1(r)^(4-1)

45/4=a1r^3

(a1*r)r^2=45/4

Substituting value of 20=a1*r

(20)r^2=45/4

r^2=45/4(20)

r^2=0.5625

r=±0.75!

answer: 2/4

step-by-step explanation:

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: